mirror of https://github.com/sbt/sbt.git
26e2449263
In Scala 2.10.4, this macro can produce a stack overflow :
def foo(a: Any): Any = macro impl
def impl(c: Context)(a: c.Expr[Any]): c.Expr[Any] = a
Here, an application such as `foo(someVal)` will produce the expansion
`someVal`. As expected, `someVal` has `original` tree `foo(someVal)`,
but if we inspect this tree, we will find that `someVal` has an
original tree, but it shouldn't.
Moreover, in Scala 2.11, some macros have their own application as
`original` trees.
See sbt/sbt#1237 for a description of these problems.
This commit fixes these two problems.
Fixes sbt/sbt#1237
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README.md
sbt
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