parser/lexical.c, #1/10, this condition is allways true
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@ -328,7 +328,7 @@ nloop:
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goto ldefault;
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case '&': /* va: $&name is one word */
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if ((i >= 1) && (buf[i-1] == '$') && (c == '&')) {
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if ((i >= 1) && (buf[i-1] == '$')) {
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buf[i++] = (char) c;
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break;
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}
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