Corrected an issue that arose due to a change made earlier: A
while back, shorted pins were moved into contiguous positions. When that method was discovered to cause matching issues, it was abandoned with a note that doing so might have unintended consequences because other code might depend on the shorted pins being contiguous. Such a case was just found, and corrected. However, it was also found that shorted pins were still not completely handled correctly in MatchPins(); a solution was found that adds such pins to the "permutes" list (which needs to be done if the shorted pins are to be correctly handled in any higher level of the hierarchy, if there is one), and the "permutes" list is then checked by MatchPins() to determine if pins match because they belong to the same group of shorted pins.
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@ -1230,6 +1230,10 @@ int UniquePins(char *name, int filenum)
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* Removed the code 9/1/2023. But---Not sure if any code depends
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* on shorted pins being adjacent.
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*/
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/* When two pins are shorted, they are by definition permutable */
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PermuteSetup(ThisCell->name, ThisCell->file, ob->name,
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firstport[ob->node]->name);
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continue;
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}
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else {
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@ -7619,10 +7619,6 @@ int MatchPins(struct nlist *tc1, struct nlist *tc2, int dolist)
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break;
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}
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}
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else {
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ob3 = NULL;
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break; /* All pins w/the same node should be together */
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}
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}
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if (ob3 == NULL) {
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if (Debug == 0) {
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@ -7670,14 +7666,6 @@ int MatchPins(struct nlist *tc1, struct nlist *tc2, int dolist)
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ob2->model.port = i; /* save order */
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*(cover + i) = (char)1;
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/* If there are multiple pins on the same net, cycle through them; */
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/* otherwise, move to the next entry in the partition. */
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if (ob1->next && (ob1->next->type == PORT) && (ob1->next->node == ob1->node)) {
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ob1 = ob1->next;
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ob2 = tc2->cell; /* Restart search for matching pin */
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i++;
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}
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else
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break;
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}
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}
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@ -7904,6 +7892,72 @@ int MatchPins(struct nlist *tc1, struct nlist *tc2, int dolist)
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if (bangptr2) *bangptr2 = '!';
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break;
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}
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else {
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struct Permutation *permute1, *permute2;
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struct objlist *ob1a = NULL, *ob2a = NULL;
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/* Check the permutation list. If any permutable pin
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* matches, and both nodes equal the nodes of their
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* pin permutations, then the pins also match.
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*/
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for (permute1 = tc1->permutes; permute1; permute1 = permute1->next) {
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if ((*matchfunc)(ob1->name, permute1->pin1)) {
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ob1a = LookupObject(permute1->pin1, tc1);
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break;
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}
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else if ((*matchfunc)(ob1->name, permute1->pin2)) {
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ob1a = LookupObject(permute1->pin2, tc1);
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break;
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}
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}
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for (permute2 = tc2->permutes; permute2; permute2 = permute2->next) {
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if ((*matchfunc)(ob2->name, permute2->pin1)) {
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ob2a = LookupObject(permute2->pin1, tc2);
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break;
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}
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else if ((*matchfunc)(ob2->name, permute2->pin2)) {
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ob2a = LookupObject(permute2->pin2, tc2);
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break;
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}
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}
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if (ob1a && ob2a) {
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if ((ob1->node == ob1a->node) && (ob2->node == ob2a->node)) {
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/* This should be enough to prove equivalency */
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if ((correspond[ob1->node] == 0) || (correspond[ob1->node] == ob2->node)) {
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correspond[ob1->node] = ob2->node; /* remember corresponding node */
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ob2->model.port = i; /* save order */
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*(cover + i) = (char)1;
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if (Debug == 0) {
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for (m = 0; m < left_col_end; m++) *(ostr + m) = ' ';
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for (m = left_col_end + 1; m < right_col_end; m++) *(ostr + m) = ' ';
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snprintf(ostr, left_col_end, "%s", ob1->name);
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snprintf(ostr + left_col_end + 1, left_col_end, "%s", ob2->name);
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for (m = 0; m < right_col_end + 1; m++)
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if (*(ostr + m) == '\0') *(ostr + m) = ' ';
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Fprintf(stdout, ostr);
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}
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else {
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Fprintf(stdout, "Circuit %s port %d \"%s\""
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" = cell %s port %d \"%s\"\n",
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tc1->name, i, ob1->name,
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tc2->name, j, ob2->name);
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}
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#ifdef TCL_NETGEN
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if (dolist) {
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Tcl_ListObjAppendElement(netgeninterp, plist1,
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Tcl_NewStringObj(ob1->name, -1));
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Tcl_ListObjAppendElement(netgeninterp, plist2,
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Tcl_NewStringObj(ob2->name, -1));
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}
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#endif
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}
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if (bangptr2) *bangptr2 = '!';
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break;
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}
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}
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}
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}
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}
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if (bangptr2) *bangptr2 = '!';
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