magic/utils/match.c

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/* match.c -
*
* String matching operations.
*
* *********************************************************************
* * Copyright (C) 1985, 1990 Regents of the University of California. *
* * Permission to use, copy, modify, and distribute this *
* * software and its documentation for any purpose and without *
* * fee is hereby granted, provided that the above copyright *
* * notice appear in all copies. The University of California *
* * makes no representations about the suitability of this *
* * software for any purpose. It is provided "as is" without *
* * express or implied warranty. Export of this software outside *
* * of the United States of America may require an export license. *
* *********************************************************************
*/
#ifndef lint
static char rcsid[] __attribute__ ((unused)) = "$Header: /usr/cvsroot/magic-8.0/utils/match.c,v 1.1.1.1 2008/02/03 20:43:50 tim Exp $";
#endif /* not lint */
#include <stdio.h>
#include "utils/magic.h"
#include "textio/textio.h"
/*
* ----------------------------------------------------------------------------
*
* Match --
*
* Sees if two strings match, using csh-like pattern matching.
*
* Results:
* TRUE is returned if the two strings match, FALSE is returned
* if they don't. The first string, pattern, can contain the
* special characters *, ?, \, and [], which are matched as by
* the csh.
*
* Side effects:
* None.
*
* ----------------------------------------------------------------------------
*/
bool
Match(pattern, string)
char *pattern; /* csh-like pattern. */
char *string; /* String to check for match against pattern.*/
{
char c2;
while (TRUE)
{
/* See if we're at the end of both pattern and string. If
* so, we succeeded. If we're at the end of pattern, but not
* of string, we failed.
*/
if (*pattern == 0)
{
if (*string == 0) return TRUE;
else return FALSE;
}
if ((*string == 0) && (*pattern != '*')) return FALSE;
/* Check for a "*" as the next pattern character. It matches
* any substring. We handle this by calling ourselves
* recursively for each postfix of string, until either we
* match or we reach the end of the string.
*/
if (*pattern == '*')
{
pattern += 1;
if (*pattern == 0) return TRUE;
while (*string != 0)
{
if (Match(pattern, string)) return TRUE;
string += 1;
}
return FALSE;
}
/* Check for a "?" as the next pattern character. It matches
* any single character.
*/
if (*pattern == '?') goto thisCharOK;
/* Check for a "[" as the next pattern character. It is followed
* by a list of characters that are acceptable, or by a range
* (two characters separated by "-").
*/
if (*pattern == '[')
{
pattern += 1;
while (TRUE)
{
if ((*pattern == ']') || (*pattern == 0)) return FALSE;
if (*pattern == *string) break;
if (pattern[1] == '-')
{
c2 = pattern[2];
if (c2 == 0) return FALSE;
if ((*pattern <= *string) && (c2 >= *string)) break;
if ((*pattern >= *string) && (c2 <= *string)) break;
pattern += 2;
}
pattern += 1;
}
while ((*pattern != ']') && (*pattern != 0)) pattern += 1;
goto thisCharOK;
}
/* If the next pattern character is '\', just strip off the '\'
* so we do exact matching on the character that follows.
*/
if (*pattern == '\\')
{
pattern += 1;
if (*pattern == 0) return FALSE;
}
/* There's no special character. Just make sure that the next
* characters of each string match.
*/
if (*pattern != *string) return FALSE;
thisCharOK: pattern += 1;
string += 1;
}
}