Fix for issue #281 - the condition operator may return a valid enum type.

If the condition expression is 2-state, the result won't be blended, so
the result will be a valid enum value if both true and false expressions
return the same enum type.
This commit is contained in:
Martin Whitaker 2019-11-09 13:11:16 +00:00
parent 7feb26ff6b
commit 82c8a49573
2 changed files with 16 additions and 0 deletions

View File

@ -2524,6 +2524,20 @@ NetETernary::~NetETernary()
delete false_val_;
}
const netenum_t* NetETernary::enumeration() const
{
// If the condition can evaluate to an ambiguous value,
// the result may be blended, and so is not guaranteed
// to be a valid enumeration value.
if (cond_->expr_type() != IVL_VT_BOOL)
return 0;
if (true_val_->enumeration() != false_val_->enumeration())
return 0;
return true_val_->enumeration();
}
const NetExpr* NetETernary::cond_expr() const
{
return cond_;

View File

@ -4757,6 +4757,8 @@ class NetETernary : public NetExpr {
NetETernary(NetExpr*c, NetExpr*t, NetExpr*f, unsigned wid, bool signed_flag);
~NetETernary();
const netenum_t* enumeration() const;
const NetExpr*cond_expr() const;
const NetExpr*true_expr() const;
const NetExpr*false_expr() const;