Allocate the correct amount of memory when escaping a string
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@ -1,5 +1,5 @@
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/*
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* Copyright (c) 2003-2016 Stephen Williams (steve@icarus.com)
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* Copyright (c) 2003-2017 Stephen Williams (steve@icarus.com)
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*
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* This source code is free software; you can redistribute it
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* and/or modify it in source code form under the terms of the GNU
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@ -37,17 +37,17 @@ PLI_UINT64 timerec_to_time64(const struct t_vpi_time*timerec)
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char *as_escaped(char *arg)
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{
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unsigned idx, cur, cnt, len = strlen(arg);
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char *res = (char *) malloc(sizeof(char *) * len);
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unsigned idx, cur, cnt, len = strlen(arg) + 1;
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char *res = (char *) malloc(sizeof(char) * len);
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cur = 0;
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cnt = len;
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cnt = len - 1;
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for (idx = 0; idx < cnt; idx++) {
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if (isprint((int)arg[idx])) {
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res[cur] = arg[idx];
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cur += 1;
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} else {
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len += 3;
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res = (char *) realloc(res, sizeof(char *) * len);
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res = (char *) realloc(res, sizeof(char) * len);
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sprintf(&(res[cur]), "\\%03o", arg[idx]);
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cur += 4;
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}
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